Posted by **benjieo** on Wednesday, May 14, 2014 at 6:40am.

In a triangle PQR. Q=8cm , R=6cm . Cosp=1/12.calculatethe value of p

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**MathMate**, Wednesday, May 14, 2014 at 6:44am
I think you mean:

In a triangle PQR. q=8cm , r=6cm . Cos(P)=1/12. Calculate the value of p.

where capital letters mean vertices, lower-case letters mean lengths of sides opposite the corresponding vertex.

Use cosine rule:

p²=q²+r²-2qr(cos(P))

and solve for p.

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