what is the lewis structure for N-bromosuccinimide?

We can't draw structure on this forum but here is a site that give the structural formula. You can add the dots and needed.

can you give me the website?

I'm sorry. That's a bad habit of mine; i.e., making a comment but not including the url.Here is is.

http://en.wikipedia.org/wiki/N-Bromosuccinimide

To determine the Lewis structure of N-bromosuccinimide (NBS), we need to know the number of valence electrons for each atom in the molecule.

N-bromosuccinimide (NBS) consists of 6 carbon atoms, 4 hydrogen atoms, 1 nitrogen atom, 1 bromine atom, and 2 oxygen atoms. Let's start by calculating the total number of valence electrons.

Carbon (C) has 4 valence electrons, and there are 6 carbon atoms present: 6 × 4 = 24 electrons.

Hydrogen (H) has 1 valence electron, and there are 4 hydrogen atoms present: 4 × 1 = 4 electrons.

Nitrogen (N) has 5 valence electrons.

Bromine (Br) has 7 valence electrons.

Oxygen (O) has 6 valence electrons, and there are 2 oxygen atoms present: 2 × 6 = 12 electrons.

Adding up all the valence electrons, we get a total of 24 + 4 + 5 + 7 + 12 = 52 electrons.

Now, let's decide on the central atom. In this case, nitrogen (N) is the central atom since it is connected to all the other atoms.

Next, we form single bonds between the central nitrogen atom and the surrounding atoms. This accounts for 4 electrons. After connecting the nitrogen atom with one of the oxygen atoms, we are left with 48 electrons.

Now, let's distribute the remaining electrons to fulfill the octet rule for each atom. We start with the outer atoms first.

The four carbon atoms each need four more electrons to complete their octet. Each carbon atom can form a single bond with one nitrogen atom, using up four electrons. We are left with 44 electrons.

The remaining eight electrons are used to form two double bonds between the remaining carbon atoms and the remaining oxygen atoms. After forming the double bonds, we are left with 36 electrons.

Finally, we distribute the remaining six electrons as lone pairs on the oxygen atoms to complete their octets. This gives us the final Lewis structure for N-bromosuccinimide (NBS).

Note: This description assumes that the molecule has a linear shape, and the connectivity of atoms is N-C-C-C-Br-O-C-C=O.

```
Br
|
O C
\ ||
C=N
/ ||
O C

```

In this structure, all atoms have a complete octet except nitrogen, which has two lone pairs of electrons.