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December 19, 2014

December 19, 2014

Posted by **J.J** on Tuesday, March 18, 2014 at 10:55pm.

1.) For the reaction, calculate how many grams of the product form when 18.4g of Ca completely reacts.

Assume that there is more than enough of the other reactant.

Ca(s)+Cl2(g)→CaCl2(s)

answer - 50.9 g.

2.) For the reaction, calculate how many grams of the product form when 18.4g of Br2 completely reacts.

Assume that there is more than enough of the other reactant.

2K(s)+Br2(l)→2KBr(s)

answer - ?

3.) For the reaction, calculate how many grams of the product form when 18.4g of O2 completely reacts.

Assume that there is more than enough of the other reactant.

4Cr(s)+3O2(g)→2Cr2O3(s)

answer - ?

4.) For the reaction, calculate how many grams of the product form when 18.4g of Sr completely reacts.

Assume that there is more than enough of the other reactant.

2Sr(s)+O2(g)→2SrO(s)

answer - ?

- Chemistry -
**DrBob222**, Tuesday, March 18, 2014 at 11:53pm2.) For the reaction, calculate how many grams of the product form when 18.4g of Br2 completely reacts.

Assume that there is more than enough of the other reactant.

2K(s)+Br2(l)→2KBr(s)

mols Br2 = grams/molar mass = estimated 0.1 but you should be more accurate than that.

Use the coefficients in the balanced equation to convert mols Br2 to mols KBr. That will be about 0.1 x (2 mol KBr/1 mol Br2) = estimated 0.2

Then convert mols KBr to g. g = mols x molar mass = about 0.2 x 119 = about 24.

ALL of these are worked the same way. The way I worked #2 will work all of them. I don't understand how you could do 1 and not do the others.

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