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posted by Sandy on Sunday, March 16, 2014 at 6:39pm.
Solve the boundary-value problem. y'' + 5y' - 6y = 0 , y(0) = 0 , y(2) = 1
y = c1 e^-6x + c2 e^x Plug in your boundary conditions, and you get c1 + c2 = 0 c1/e^12 + c2/e^2 = 1 Now just solve for c1 and c2
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