An object with an initial velocity of 12 m/s west experiences a constant acceleration of 4 m/s^2 west for 3 seconds. During this time the object travels a distance of:

54

V = Vo + a*t = 12 + 4*3 = 24 m/s = Final

velocity.

d=(V^2-Vo^2)/2a = (24^2-12^2)/8 = 54 m.

To find the distance traveled by the object, we can use the equation of motion:

distance = initial velocity * time + (1/2) * acceleration * time^2

Given:
Initial velocity (u) = 12 m/s west
Acceleration (a) = 4 m/s^2 west
Time (t) = 3 seconds

Plugging the values into the equation:

distance = (12 m/s) * (3 s) + (1/2) * (4 m/s^2) * (3 s)^2

distance = 36 m + (1/2) * 4 m/s^2 * 9 s^2

distance = 36 m + 18 m

distance = 54 meters

Therefore, the object travels a distance of 54 meters.

To find the distance traveled by the object during the given time, we can use the kinematic equation:

distance = initial velocity * time + 0.5 * acceleration * time^2

Given:
Initial velocity (u) = 12 m/s west (negative direction)
Acceleration (a) = 4 m/s^2 west (negative direction)
Time (t) = 3 seconds

To use this equation, we need to make sure the quantities are in the same direction. In this case, since both the initial velocity and acceleration are in the west direction, we can consider them as negative quantities. So, we will use the negative sign to indicate their direction.

Substituting the given values into the equation:

distance = (12 m/s) * (3 s) + 0.5 * (-4 m/s^2) * (3 s)^2

Simplifying the equation:

distance = 36 m - 18 m = 18 m

Therefore, the object travels a distance of 18 meters in the west direction.