Calculate the specific heat \((\rm{J/g \; ^\circ C})\) for a 18.5-\(\rm g\) sample of tin that absorbs 183 \({\rm J}\) when temperature increases from 35.0 \(^\circ \rm C\) to 78.6 \(^\circ \rm C\).
18.5 what? grams?
q = mass x specific heat x (Tfinal-Tinitial)
q = 183 J
mass = 18.5g
solve for sp.H.
Tfinal = 78.6
Tinitial = 35.