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Posted by on Monday, September 23, 2013 at 9:32pm.

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 5.48 m/s. The car is a distance d away. The bear is 30.5 m behind the tourist and running at 6.67 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

  • Phyics - , Wednesday, September 25, 2013 at 3:08pm

    both take the same amount of time, t
    distance of tourist from car d = 3.8 t
    distance of bear from car = 3.8 t + 27 = 6 t
    so
    2.2 t = 27
    t = 270/22= about 12.3 seconds
    d = 3.8 t = 3.8 * 270/22 = 46.6 m max

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