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July 31, 2014

July 31, 2014

Posted by **joanna** on Wednesday, September 18, 2013 at 5:00am.

- math -
**Graham**, Wednesday, September 18, 2013 at 5:56amSome details of the question appear to be missing.

I'm assuming the pen is to be rectangular and further that you want to find the length and width that enclose the maximum possible area.

Let the width of the pen be x, so that the length is 20-3x the area (y) is:

y = 20 x -2 x^2

y' = 20 -4 x

Maximum area exists when y'=0

Solve for x.

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