Posted by **vincent** on Saturday, August 3, 2013 at 6:16pm.

The fraction 5Y3X/2Y8, in which x and Y stand for two unknown digits, represents a division which results in a quotient that is a whole number. Which of the following is (are) true?

1. X may equal 2.

11. X may equal 6 or 0.

111. X may equal 4.

not just and answer, i don't get this question very much.

A.1 only

B.11 only

C.111 only

D.1 and 111 only

E.1,11,and 111

- math -
**Henry**, Saturday, August 3, 2013 at 9:00pm
3X5Y/2Y8 = 15x/16.

15x/16 = 1 = The smallest whole number.

15x = 16

X = 16/15 = 1 1/15.

According to my analysis, x cannot equal

0,2,4, nor 6.

- math -
**Reiny**, Saturday, August 3, 2013 at 9:01pm
f y=0 --> 503?/208 = appr 24

to be exact 24*208 = 4992 , so y ≠ 0

if y = 1 --> 513?/218 = appr 24

24*218 = 5232 , so y≠1

y=2 --> 523?/228 = 23

23*228 = 5244 , so y≠2

y=3 --> 533?/238 = appr 22

22*238 = 5236 , so y≠3

y = 4 --> 543?/248 = appr 22

22*248 = 5456 , so y≠4

y = 5 --> 553?/258 = appr 21

21*258 = 5418 , so y≠5

y = 6 --> 563?/268 = appr 21

21*268 = 5628

20*268 = 5360 , y ≠ 6

y = 7 -> 573?/278 = appr 21

21*278 = 5838

20*278 = 5560 , y ≠ 7

y = 8 --> 583?/288 = appr 20

20*288 = 5760

21*288 = 6048

19*288 = 5472 , y ≠ 8

y = 9 --> 593?/298 = appr 21

21*298 = 6258

20*298 = 5960

22*298 = 6556

I have exhausted all possible choices for y from 0 to 9

since x depends on what y values we choose,

and unless I made an arithmetic error, no values of x and y make the statement true.

- math -
**vincent**, Saturday, August 3, 2013 at 10:13pm
I. X may equal 2.

II. X may equal 6 or 0.

III. X may equal 4.

A.I only

B.II only

C.III only

D.I and III only

E.I,II,and III

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