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Solve the following system of equations using the cross multiplication method,ax+by=a-b;bx-ay=a+b

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    http://www.mathcaptain.com/algebra/simultaneous-equations.html

    ax +by =a-b
    bx-ay=a+b

    ax+by +(b-a) = 0
    bx –ay +(-a-b) = 0
    x y 1
    --------------------------------
    b ↘ b-a ↘ a ↘ b
    -a ↗ -a-b ↗ b ↗ -a
    x/{-ab-b²+ab-a²} = y/{b²-ab+a²+ab} = 1/{-a²-b²},
    x/{-a²-b²} = 1/{-a²-b²},
    x=1.
    y/{b² +a²} =1/{-a²-b²},
    y=-1.

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