Posted by **Lavinia** on Monday, July 8, 2013 at 3:21am.

Solve the following system of equations using the cross multiplication method,ax+by=a-b;bx-ay=a+b

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**Elena**, Monday, July 8, 2013 at 6:27am
http://www.mathcaptain.com/algebra/simultaneous-equations.html

ax +by =a-b

bx-ay=a+b

ax+by +(b-a) = 0

bx –ay +(-a-b) = 0

x y 1

--------------------------------

b ↘ b-a ↘ a ↘ b

-a ↗ -a-b ↗ b ↗ -a

x/{-ab-b²+ab-a²} = y/{b²-ab+a²+ab} = 1/{-a²-b²},

x/{-a²-b²} = 1/{-a²-b²},

x=1.

y/{b² +a²} =1/{-a²-b²},

y=-1.

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