Posted by SAFEWAY on Thursday, May 9, 2013 at 3:20pm.
The builtin composite bar BC of length L=2 m is composed of two materials with equal cross sectional area A = 100 mm2. The first material has elastic modulus E=1 GPa. The second material is twice as stiff, with a modulus of 2E or 2 GPa. The bar is subjected to an unknown distributed load fx(x), and to an unknown concentrated load F at an unknown position along the bar. As a result of these loading conditions, the displacement field of the bar is:
ux(x)={−aLx,2a(x2−Lx),if 0≤x<L/2if L/2<x≤L
where a= 0.01 [1/m] is a dimensional constant.

PHYSIC  access, Friday, May 10, 2013 at 11:05am
u1 = a*L*x1;
u2 = 2*a*(x2.^2L*x2);

PHYSIC  access, Friday, May 10, 2013 at 12:23pm
N1 = 3*a*L*A*E+0*x1;
N2 = 6*a*A*E*(2*x2L);

PHYSIC  access, Friday, May 10, 2013 at 12:29pm
fx1 = 0 + 0*x1;
fx2 = 12*a*A*E + 0*x2;

PHYSIC  access, Friday, May 10, 2013 at 12:56pm
Fx = 3*a*L*A*E
x = L/2

PHYSIC  access, Friday, May 10, 2013 at 1:01pm
Rx(B) = 3*a*A*E*L
Rx(C) = 6*a*A*E*L

PHYSIC  FLu, Friday, May 10, 2013 at 5:12pm
Thanks Access!
Do you have HW3_2A and 2B?

PHYSIC  Anonymous, Friday, May 10, 2013 at 9:53pm
thanks a lot access!

PHYSIC  Pa, Saturday, May 11, 2013 at 6:23am
HW3_2A
N(x)= (2*p_0*L)/27p_0*(L/3x+(3*x^2)/(4*L))
N(x)=(2*p_0*L)/27

PHYSIC  Pa, Saturday, May 11, 2013 at 7:02am
HW3_2B
0<x<(2/3)L
(2*p_0*L*x)/(27*E*A)p_0/(E*A)*((L*x)/3x^2/2+x^3/(4*L))

PHYSIC  FLu, Saturday, May 11, 2013 at 8:51am
Many thanks Pa!

PHYSIC  Mag, Saturday, May 11, 2013 at 8:54am
THanks!
The second for HW3_2B please?
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