Find the standard deviation, Sigma, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth.
n = 639; p = 0.7
standard deviation = √npq
n = 639
p = 0.7
q = 1 - p
I'll let you take it from here to calculate.
To find the standard deviation (sigma) for a binomial distribution, you can use the following formula:
σ = √(n * p * (1 - p))
Given n = 639 and p = 0.7, we can substitute these values into the formula and calculate the standard deviation.
σ = √(639 * 0.7 * (1 - 0.7))
σ = √(449.73)
σ ≈ 21.21
Therefore, the standard deviation (sigma) for the binomial distribution with n = 639 and p = 0.7 is approximately 21.21.
To find the standard deviation, Sigma, for the binomial distribution, you can use the formula:
Sigma = sqrt(n * p * (1 - p))
where n is the number of trials and p is the probability of success on each trial.
Given n = 639 and p = 0.7, substitute these values into the formula:
Sigma = sqrt(639 * 0.7 * (1 - 0.7))
Now, calculate the expression inside the square root:
1 - 0.7 = 0.3
639 * 0.7 = 447.3
0.3 * 447.3 = 134.19
Sigma = sqrt(134.19)
Now, round the result to the nearest hundredth:
Sigma ≈ sqrt(134.19) ≈ 11.58
Therefore, the standard deviation, Sigma, for the given binomial distribution is approximately 11.58.