a bus that is traveling at 30.0km/h speeds up at a constant rate of 3.5m/s2. what velocity does it reach 6.8s later?

24.633m/s

suppose a car travels @ a constant 15m/s how far would it move in 1.5hr? in 1min? 20sec?

To find the velocity of the bus after 6.8 seconds, we can use the formula for constant acceleration:

Final velocity (v) = Initial velocity (u) + (Acceleration (a) x Time (t))

Given information:
Initial velocity (u) = 30.0 km/h (which needs to be converted to m/s)
Acceleration (a) = 3.5 m/s²
Time (t) = 6.8 s

First, let's convert the initial velocity from km/h to m/s:
To convert from km/h to m/s, we can divide by 3.6 since 1 km/h is equal to 1/3.6 m/s.

Initial velocity (u) = 30.0 km/h ÷ 3.6 = (30.0 ÷ 3.6) m/s ≈ 8.33 m/s (rounded to two decimal places)

Now we can substitute the values into the formula:

Final velocity (v) = 8.33 m/s + (3.5 m/s² x 6.8 s)

To calculate this, multiply the acceleration by the time:

Final velocity (v) = 8.33 m/s + (3.5 m/s² x 6.8 s)
= 8.33 m/s + 23.8 m/s
= 32.13 m/s

Therefore, the bus will reach a velocity of approximately 32.13 m/s (rounded to two decimal places) after 6.8 seconds.