Posted by Brieson on Friday, March 22, 2013 at 3:16pm.
3x^2 + 7x-6
(X+3)(3x-2)
3x^2 + 7x - 6
multiply the first and last coefficients
3(-6) = -18
factors of -18 that add up to 7
+9 and -2
(9)(-2) = -18 and 9 - 2 = 7
so replace the middle term of 7x with -2x + 9x
3x^2 - 2x + 9x -6
group as
(3x^2 - 2x) + (9x-6)
now factor each group
x(3x-2) + 3(3x-2)
= (3x-2)(x+3)
x=2/3 and x=-3