Calculate the volume of oxygen starndad temperature and pressure which theoretically could be obtained from the 50cm3 of the solution of hydrogen peroxide containing 68g/dm3
From; Concentration g/dm3=mass g/Volume(dm3)
So you can make the subject mass(g) =conc×volume
Mass of H2O2=68g/dm3×0.05dm3
Mass of H2O2= 3.4g
Then moles of H2O2= Mass/Molarmass
Moles of H2O2= 3.4g/34g/mol
Moles of H2O2=0.1mol
From the balanced decomposition reaction of hydrogen peroxide
2mol of H2O2 =1mol of oxygen
0.1mol of H2O2=? Mol of oxygen
= 0.05 moles of oxygen
At s.t.p number of moles of oxygen= v/V
Volume required=number of moles of oxygen ×V (s.t.p)
V=0.05mol ×22.4dm3
Volume of oxygen=1.12dm3
Ok abel yona john sagali
68 g x *50 cc/1000 dm^3 = ? g H2O2.
mols H2O2 = grams/molar mass.
Then you know 1 mol occupies 22.4L a STP.
To calculate the volume of oxygen that can be obtained from the given solution of hydrogen peroxide, we need to use the chemical equation for the decomposition of hydrogen peroxide:
2H2O2 -> 2H2O + O2
From the balanced equation, we can see that for every 2 moles of hydrogen peroxide (H2O2), we get 1 mole of oxygen gas (O2).
To start, we need to find the number of moles of hydrogen peroxide in the given solution. To do this, we can use the formula:
Moles = Mass / Molar Mass
The molar mass of hydrogen peroxide (H2O2) is calculated as:
2( Hydrogen's atomic mass ) + 2( Oxygen's atomic mass ) = (2 * 1) + (2 * 16) = 34 g/mol
Now, we can calculate the number of moles of hydrogen peroxide:
Moles = 68 g/dm3 / 34 g/mol
Since the volume is given in cm3, we need to convert it to dm3:
Volume = 50 cm3 / 1000 = 0.05 dm3
Now, we can calculate the number of moles of hydrogen peroxide in the given volume:
Moles = 68 g/dm3 / 34 g/mol * 0.05 dm3
Next, we need to determine the number of moles of oxygen gas formed based on the stoichiometry of the balanced chemical equation.
Since the balanced equation shows that 2 moles of hydrogen peroxide yield 1 mole of oxygen gas, we can divide the number of moles of hydrogen peroxide by 2 to get the moles of oxygen gas:
Moles of oxygen gas = Moles of hydrogen peroxide / 2
Finally, to calculate the volume of oxygen gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (given)
V = volume of oxygen gas (unknown)
n = number of moles of oxygen gas (from the previous step)
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (given)
Rearranging the equation to solve for V:
V = (nRT) / P
By substituting the values, we can calculate the volume of oxygen gas:
V = (Moles of oxygen gas * R * T) / P
Remember to pay attention to the units used (e.g., convert temperature to Kelvin, pressure to atm, etc.) and ensure they are consistent throughout the calculation.
Please provide the values for temperature and pressure to complete the calculation.