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What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
1 answer
The dilution formula is
c1v1 = c2v2
c = concn
v = volume
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What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
Top answer:
How many moles do you need? That is M x L = 3.0M x 0.250L = ? Then moles = grams/molar mass. Solve
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What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
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I would use the dilution formula. M1V1 = M2V2
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What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
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Use c1v1 = c2v2 c= concn v = volume
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What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
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c1v1 = c2v2 c = concn v = volume 6.0*v = 3.0*250. v = ? in mL.
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What volume of a 6.0 M NaOH solution would you need to prepare 250.0 milliliters of a 3.0 M NaOH solution?
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