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December 19, 2014

December 19, 2014

Posted by **Anonymous** on Monday, February 18, 2013 at 7:34pm.

f(x)=1/x^2-5

Can't remember how to solve, your help is appreciated:-)

- college algebra -
**Jeff**, Monday, February 18, 2013 at 7:37pmIf X^2-5 is the denom, then the domain would be all X such that the denom does not equal 0.

So find when x^2-5=0

x=sqrt(5) (Both positive and negative)

So the domain is all real numbers, such that X does not equal +- sqrt (5)

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