Monday

April 21, 2014

April 21, 2014

Posted by **Anonymous** on Monday, January 28, 2013 at 6:54am.

- physics -
**Elena**, Monday, January 28, 2013 at 9:59amFig.1: path difference Δ₁=0, since distances between each loudspeaker and point O are L

For constructive interference Δ₁=2kλ/2=kλ (k(min)=0) => Δ₁=0.

Fig.2:

path difference Δ₂=L√2 – L= L(√2 –1)= 0.41L=0.353 m

For destructive interference

Δ₂=(2k+1)λ/2= λ/2,

k(min)=0 => Δ₁=λ/2 =0.353 m

=> λ =2•0.353 =0.706 m

λ=v/f => f= v/λ=

=343/0.706 = 485.8 Hz

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