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September 1, 2014

September 1, 2014

Posted by **Kiana** on Saturday, January 12, 2013 at 10:00pm.

- physics -
**drwls**, Saturday, January 12, 2013 at 10:27pmdv/dt = 2/v^2

v^2*dv = 2 dt

Integrate both sides from t=0, v=0

v^3/3 = 2 t

v = [6 t]^1/3

Check: a = dv/dt = (1/3)*(6 t)^-2/3*6

= 2*(6t)^-2/3 = a/v^2

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