Posted by zamarra on Friday, January 11, 2013 at 12:25am.
how to factor (2a+3b)^24c(2a+3b)+4c2

algebra  drwls, Friday, January 11, 2013 at 2:01am
Let 2a + 3b = d
Then it becomes
d^2 4cd + 4c^2 = (d2c)^2
Therefore it factors as
(2a + 3b 2c)^2