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posted by zamarra on Friday, January 11, 2013 at 12:25am.

how to factor (2a+3b)^2-4c(2a+3b)+4c2

Let 2a + 3b = d Then it becomes d^2 -4cd + 4c^2 = (d-2c)^2 Therefore it factors as (2a + 3b -2c)^2

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