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December 21, 2014

December 21, 2014

Posted by **Kelly** on Friday, January 4, 2013 at 12:48pm.

- statistics -
**MathMate**, Friday, January 4, 2013 at 7:11pmCalculate the Z-score:

Z=(10-5.7)/1.8=2.39

Look up the normal distribution table for the corresponding probability for LESS than 10 years, subtract this probability from 1.0 to get the probability of service of 10 years or more.

Table link:

http://www.math.unb.ca/~knight/utility/NormTble.htm

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