Posted by Daryl on Friday, December 7, 2012 at 3:19pm.
First use conservation of momentum to calculate the final velocity of both, V.
75*2 - 70*1.5 = 145 V
V = 0.31 m/s (west)
Now add up the initial and final kinetic energies.
KE1 = (1/2)*75*2^2 + (1/2)*70*(1.5)^2
= 150+ 78.75 = 228.75 J
KE2 = (1/2)*145*(0.31)^2 = 6.97 J
Subtract for the KE Loss. About 97% of the initial KE is lost.
Related Questions
physics - 1. A football player weighing 75 kg running at 2 m/s toward west ...
physics - Here's a basketball problem: A 83.0 kg basketball player is ...
physics - 9)Which has more momentum? A .1 kg toy truck moving at 1012 m/s or a ...
physics - a football player runs at 8 m/s and plows into a 80 kg referee ...
Physics - A 120 kg football player tries to dive into the endzone at 7.5 m/s to ...
geometry - During the half-time show of a football game, a trumpet player and a ...
physics - An 85 kg football player traveling 4.7 m/s is stopped in 1.0 s by a ...
Science - A football player has to push a blocking sled the length of a football...
physics - A 0.36 kg soccer ball approaches a player horizontally with a velocity...
Physics - A 0.48 kg soccer ball approaches a player horizontally with a velocity...
For Further Reading
