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April 2, 2015

April 2, 2015

Posted by **Mikey** on Sunday, December 2, 2012 at 6:44pm.

At 6.38x10^3 km away from Earth's surface a spacecrafts weight is d=rE+rE

Then F=(1/4)(SpaceCraftWeight)

Why is the distance 2rE?

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