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chemistry

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a. Find the amount of solute based on this information
Volume = 500 ml
Concentration of solution= 15% (w/w)
Solute (molar mass) = H2SO4 is 98.0g/mol
b. Find the molar mass
Amount of solute= 117.0g
Volume of solution= 2.00L
concentration of a solution= 1.0M
volume of solvent = 2.00L
c. find the concentration of the solution (ppm) w/w
solute = 180g/mol(C6H12O6)
amount of solute= 0.0150mg
volume of solvent= 0.125L
d. find the volume of solvent
solute=60.0g/mol(CH3COOH)
amount of solute= 25.0 ml
concentration of solution= 5.00% v/v

  • chemistry - ,

    500 mL doesn't mean anything without the density. 15% w/w means 15 g H2SO4/100 GRAMS soln. So in 500 GRAMS of soln there is
    15 g H2SO4 x 500/100 = ? but in 500 mL who knows.

  • chemistry - ,

    water is the solvent and it is aasumed its density is 1.0g/cc pls need simple explanation forall of this problems

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