Posted by Anonymous on Friday, November 23, 2012 at 3:03pm.
I assume you know the formula for the length of a curve in Calculus.
L = ∫( 1 + (dy/dx)^2 )^(1/2) dx (from left x to right x)
This is the hard part of the question
I ended up finding the length of the parabolic curve to be
L = 2∫(1 + 4x^2)^(1/2) dx from x=0 to x=2
I ran this through WolFram to get
http://integrals.wolfram.com/index.jsp?expr=%281%2B+4x%5E2%29%5E%281%2F2%29&random=false
sub in the values, add on the distance from (-2,4) to (2,4) and you have the perimeter of R
For the area:
A = 2∫(4 - x^2) dx from x = 0 to 2
which you should be able to do quite easily.
The length of the curve is the only difficult part of the problem.
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