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September 30, 2014

September 30, 2014

Posted by **nono** on Tuesday, November 20, 2012 at 1:37pm.

- biostatistic -
**MathGuru**, Tuesday, November 20, 2012 at 7:19pmUse a one-sample z-test.

z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)

With your data:

z = (38 - 60)/(19/√50) = ?

Finish the calculation.

Check a z-table at .05 level of significance for a one-tailed test.

If the z-test statistic exceeds the critical value from the z-table, reject the null and conclude µ < 60 (which is the alternative hypothesis). If the z-test statistic does not exceed the critical value from the z-table, do not reject the null.

I hope this will help get you started.

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