Posted by
**michelle** on
.

Three masses are arranged in the (x, y)

plane.

3kg (0,0)

7kg (10,0)

6kg (0,3)

What is the magnitude of the resulting

force on the 3 kg mass at the origin? The value of the universal gravitational constant is 6.6726 × 10^−11 N · m^2/kg^2.

Answer in units of N

what ive done

G*(7)*(3)/10^2 = 1.401246*10^-11

G*(3)*(6)/3^2 = 1.33452*10^-10

sqrt((1.401246*10^-11)^2 + (1.33452*10^-10)^2)

= 1.341856376*10^-10

my program tells me im wrong. im getting frustrated. please help?