Thursday

December 18, 2014

December 18, 2014

Posted by **B** on Monday, November 5, 2012 at 2:48pm.

a) Find the acceleration of the box.

b) If the box is at rest to start with, what is its speed after it has traveled 2.00 m?

c) How much time does it take to pull the box this distance?

Please show how you got there! This problem has stumped me..

- Physics -
**Henry**, Wednesday, November 7, 2012 at 5:23pmWb = m*g = 22kg * 9.8N/kg = 215.6 N. =

Wt. of box.

Fb = 215.6N @ 0o. = = Force of box.

Fp = 215.6*sin(0) = 0 = Force parallel to floor.

Fv = 215.6*cos(0) - 92*sin30 = 169.6 =

Force perpendicular to floor=The Normal.

Fk = u*Fv = 0.5 * 169.6=84.8 N. = Force

of kinetic friction.

a. Fap*cos30-Fp-Fk = m*a.

92*cos30-0-84.8 = 22a

22a = -5.12

a = -0.23 m/s^2. This should not be

negative. Make sure all given INFO is

correct.

b. V ^2 = Vo^2 + 2a*d

**Answer this Question**

**Related Questions**

Physics - At the beginning of a new school term, a student moves a box of books ...

college physics - A student moves a box of books by attaching a rope to the box ...

physics - A student moves a box of books down the hall by pulling on a rope ...

Physics - A student moves a box of books down the hall by pulling on a rope ...

physics - A student pulls on a rope attached to a box of books and moves the box...

Physics - A student decides to move a box of books into her dormitory room by ...

Physics - A student decides to move a box of books into her dormitory room by ...

physics - a college student takes her book to class by placing them in a box and...

physics - a college student takes her book to class by placing them in a box and...

Physics - A physics student is pulling on a 20 kg box that is sliding on the ...