Posted by Ian on Friday, October 26, 2012 at 9:24pm.
I assume you made a sketch.
You should have the two graphs intersecting at (0.0) and (16,4)
So we will washer discs with outer ratius of 4 - x/4 and inner radius of 4 - √x
area of washer disc = π(4-x/4)^2 = π(4-√x)^2
= π(16 - 2x + x^2/4 - (16 - 8√x + x)
= π( -3x + x^2 + 8x^(1/2)
volume = π∫(-3x + x^2 + 8x^(1/2) dx from 0 to 16
= π [ (-3/2)x^2 + (1/3)x^3 + (16/3)x^(3/2) ] from 0 to 16
= π(-384 + 4096/3 + 1024/3 - 0]
= π(3968/3)
check my arithmetic
Related Questions
Calculus - The region between the graphs of x=y^2 and x=4y is rotated around the...
CALCULUS:) - The region between the graphs of x=y^2 and x=6y is rotated around ...
Calculus - The region between the graphs of x=y^2 and x=6y is rotated around the...
Calculus - This is a tough one :( The region between the graphs of x=y^2 and x=...
math - The region between the graphs of y=x^2 and y=2x is rotated around the ...
math - The region between the graphs of x=y2 and x=5y is rotated around the ...
math - The region between the graphs of x=y2 and x=5y is rotated around the ...
math - The region between the graphs of x=y2 and x=5y is rotated around the ...
calculus - The region between the graphs of y=x^2 and y=2x is rotated around the...
Calculus - This problem set is ridiculously hard. I know how to find the volume ...
For Further Reading
