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December 20, 2014

December 20, 2014

Posted by **Angela** on Saturday, September 29, 2012 at 9:30pm.

- College math -
**Reiny**, Saturday, September 29, 2012 at 10:08pm-30/10 = -3

a14/a^17 = 1/a^3 or a^-3

b^8/b^-2 = b^10

so -30a^14b^8/(10a^17b^-2)

= -3 a^-3 b^10 or -3b^10/a^3

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