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October 26, 2014

October 26, 2014

Posted by **batmo** on Monday, September 24, 2012 at 12:06am.

10(cos 137° – isin 137°)

0.4(cos 137° + isin 137°)

0.4(cos 137° – isin 137°)

10(cos 137° + isin 137°)

- Calculus -
**Reiny**, Monday, September 24, 2012 at 12:33ammultiply top and bottom by the conjugate of the denominator, that is, multiply top and bottom by

(cos11 - isin11)

(I will skip the ° sign)

expand and simplify to get

(2/5) (cos148cos11 - icos148sin11 + isin148cos11 - i^2sin148sin11)/(cos^2 11 - i^2 cos^2 11)

= (2/5) (cos148cos11 - cos148sin11 + i(sin148cos11 - cos148sin11)/ 1

= .4( cos(148-11) + i(sin(148-11))

= .4(cos 137 + sin137)

which is one of the choices.

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