Operations with Complex Numbers

Welcome to the "Operations with Complex Numbers" category on Questions LLC! Complex numbers are an essential and fascinating branch of mathematics, and this category offers a plethora of questions and answers to help you enhance your understanding of their manipulation and properties. Whether you are a student struggling with complex number operations or a math enthusiast looking to deepen your knowledge, you've come to the right place. Engage in lively discussions, explore various techniques, and find solutions to the most perplexing problems related to complex number operations. We encourage you to browse through the questions and answers provided by our knowledgeable community and contribute your insights to enrich this engaging math-oriented platform. Enjoy your exploration of "Operations with Complex Numbers"!

Questions (75)

What is the product of a complex conjugated?The product of complex conjugates is a difference of two squares it is always a real
1. 4 answers
2. asked by Lacey
3. 2,401 views
Operations with Complex NumbersSimplify. 1. sqrt(-144) 2. sqrt(-64x^4) 3. sqrt(-13)*sqrt(-26) 4. (-2i)(-6i)(4i) 5. i13 6. i38 7.
1. 1 answer
2. asked by Brian
3. 1,079 views
demoivre theorem(2sqrt3+2i)^5 r=(2sqrt3+2)^2
1. 3 answers
2. asked by LK
3. 787 views
1. Given z1 = 2(cos pi/6 + i sin pi/6) and z2 = 3 (cos pi/4 + i sin pi/4), find z1z2 where 0 ≤ theta ≤ 2pi2. Find the
1. 1 answer
2. asked by Precal
3. 99 views
(1+(2*I))/(3-(4*I))+2/5
1. 2 answers
2. asked by Hamza
3. 64 views
Root of iota plus root of minus iota
1. 5 answers
2. asked by Raghuveer
3. 3,299 views
Perform the indicated operations and write the answer in the form a + bi, where a and b are real numbers.Problem #1 (3+2i)^2
1. 10 answers
2. asked by Dawn
3. 1,869 views
Find the product of 9 -5i and its complex conjugate
1. 3 answers
2. asked by Anonymous
3. 1,900 views
For z1 = 4cis (7pi/6) and z2 = 3cis(pi/3), find z1 * z2 in rectangular form.
1. 3 answers
2. asked by Sam
3. 1,757 views
How do you do this problem?1+i(square root of 3)
1. 1 answer
2. asked by Kevin
3. 307 views
write the sum or difference in the standard form a+bi(2-3i)+(6+5i) (squareroot5-3i)+(-2+squareroot-9)
1. 3 answers
2. asked by tim
3. 693 views
fin the product z1 * z2 and quotient z1/z2 using the standard form for z1 and z2.z1 = 2 - 3i and z2 = 1 - sqrt 3i
1. 3 answers
2. asked by Yoshi
3. 1,361 views
How many solutions can you get? 3i + 2i - 4 = 18i
1. 2 answers
2. asked anonymously
3. 32 views
Four complex numbers lie at the vertices of a square in the complex plane. Three of the numbers are 1+2i,-2+i and -1-2i. What is
1. 2 answers
2. asked by m
3. 128 views
(10+9i)⋅ ¯¯¯¯¯¯(10+9i) Perform the indicated operation & simplify. Express the answer in terms of i (as a complex
1. 1 answer
2. asked by Rafi
3. 73 views
Perform the operation and write the result in standard form.(√19 + √20i)(√19 – √20i)
1. 5 answers
2. asked by Kayla
3. 317 views
Let z=-8+15i and w=6-8i. Computezz/ww (each of the second ones, z and w, have a bar over them) where the bar represents the
1. 3 answers
2. asked by Mark
3. 593 views
1. What is the sum of the complex numbers: (−9−i)+(−5−i)?A. −14−2i B. −14+2i C. 14−2i D. 14+2i 2. What is the
1. 3 answers
2. asked by KiriBakuTodoDeku
3. 41 views
Do the operation and write in the form a + bi.1/(7 + i) Is this 7/50 - (1/50)i?
1. 1 answer
2. asked by Anonymous
3. 338 views
write in standard form a+bi: (2+3i)^3
1. 1 answer
2. asked by Tim
3. 297 views
Let Z be equal to (2-5i)The question is z^2 +iz -(5+i) The answer I got for this was -22 + 18i but it isn't correct on my
1. 1 answer
2. asked by Anonymous
3. 346 views
Write the following in a+bi form(-5-i)/(3-3i) -5/3 and 1/3i (-5/2i)/(-1/5i) 23 and 0i (-2i)^3 -2 and 0 Im having trouble with
1. 1 answer
2. asked by Anonymous
3. 364 views
Write the following a+bi formi(3.14-3i) Please help. I believe that the answer is 3.14i-3i, which would be (3.13*-1)-3*-1.
1. 1 answer
2. asked by Anonymous
3. 340 views
express in form a+bi(1+2sqrt3)(2-3sqrt-3) so I came up with 2-3i sqrt3 + 4sqrt3 - 18i Is that solution a+bi form
1. 1 answer
2. asked by Terri
3. 358 views
Write the number in the form a + bi:square root -9 + 16 i got 16 +3i is that right
1. 1 answer
2. asked by lisa
3. 278 views
Given w=2+2i and v=−5√3+5i,vw^2 can be expressed as r*(cos(α∘)+i*sin(α∘)), where r is a real number and 0≤α≤360.
1. 3 answers
2. asked by Crow
3. 363 views
i^59 and 4____ 3+5i
1. 1 answer
2. asked by Wanda
3. 293 views
express in terms of isquare -225 + square -49
1. 1 answer
2. asked by TB
3. 271 views
I got this answer for a problem, and I'm not sure if it's right.Can someone tell me if I'm correct? 1.(2+4i / 3-i) = 6/7+5/7i
1. 6 answers
2. asked by Tara
3. 287 views
Check Answers Please?1. 5+(2+3i) + (-3-7i) = 4 + -4i 2. (5-10i) - (2+i) = 7 - 9i 3. -5i(2-3i) = -10i - 15 4. (2+3i)(-3-7i) =
1. 7 answers
2. asked by Sara
3. 614 views
Which of the following re-expresses the negative square root √-40 as a complex number in the standard form a + bi?2√10
1. 3 answers
2. asked anonymously
3. 71 views
Find (-1+i)^1/3 list steps
1. 3 answers
2. asked by 95
3. 370 views
1. Find (-1+i)^1/32. Express 2(cos5pi/3 + isin5pi/3) in regular form. would this be correct: 1-√3i? 3. Find (2+4i)^3 in
1. 3 answers
2. asked by 95
3. 399 views
Dividing: Write the expression as a complex number in standard form1) 2+5i/5+2i 2) 6-i√2/6+i√2 for the first one I solved it
1. 1 answer
2. asked by Linda
3. 385 views
find zwz=8(cospi/2+isinpi/2) w=4(cospi/4+isinpi/4)
1. 1 answer
2. asked by joe
3. 335 views
Subtract 75–√−4–√5.(1 point)
1. 3 answers
2. asked by Help.I.Don't.Know.The.Answer.
3. 74 views
Is this right?(4-i)(-3+4i) -12+16i+3i-4i^2 -12+19i+4 -8+19i (answer)
1. 1 answer
2. asked by Amy~
3. 293 views
(2-2i)^5find the given power write answer in rectangular form
1. 2 answers
2. asked by stacey graham
3. 676 views
convert the numbers to polar form and then divide.leave the answer in polar form. 10-10i/3root3+3i
1. 1 answer
2. asked by javed
3. 394 views
subtract: 3+5i-(-4+6i) is the answer 7-i?
1. 1 answer
2. asked by Shawn
3. 239 views
I just need help with these questions, thanks.i^5 3(-2i)^2 -i(isqrt5)^2
1. 3 answers
2. asked by Lucy
3. 362 views
I need help with writing the quotient of this complex number in standard form:(1 + 4i)/(5 - 12i)
1. 1 answer
2. asked by Brian
3. 412 views
I some problems that I need help with please.Add or subtact as indicated and write the results in standard form. 4.
1. 3 answers
2. asked by Aly
3. 720 views
simplify the following expressions involving complex numbers.(3+2i)-(-7-i) 10 + 3i how did you do that? can you show me this one
1. 2 answers
2. asked by Shay
3. 843 views
Which of the following re-expresses the negative square root −6−20−−−−√ as a complex number in the standard form
1. 1 answer
2. asked anonymously
3. 70 views
Given the complex number 7–√−6i, determine the real part and the imaginary part.(1 point) is the real part of the complex
1. 1 answer
2. asked anonymously
3. 24 views
subtract.(1+2i)-(3+8i)
1. 1 answer
2. asked by zaynab
3. 15 views
5-4i/9+4i
1. 1 answer
2. asked by zaynab
3. 17 views
Subtract the complex numbers (12−8i)−(−4+3i) .(1 point) Responses 16−11i 16 minus 11 i 8−11i 8 minus 11 i 16−5i 16
1. 1 answer
2. asked anonymously
3. 36 views
use the properties of complex numbers to simplify (√-49 +5i)+(8-√-4).- 8+14i - 13+9i - 8+10i - 8+5i+√-53
1. 1 answer
2. asked anonymously
3. 38 views

Operations with Complex Numbers

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