Hello

I have to determine the theoritical yield of sulfanilamide after crystalization of impure sulfanilamide with 95% ethyl alcohol (the impure sulfanilamide contains 5% Fluorenone)

I understand how to calculate the theoretical yield, my problem is determining the chemical equation of the reaction so I can do the mole ratio.

Help please!!!!

Hello!

To determine the theoretical yield of sulfanilamide after crystallization with ethyl alcohol, you need to know the balanced chemical equation for the reaction between sulfanilamide and ethyl alcohol.

The reaction between sulfanilamide (C6H7N3O2S) and ethyl alcohol (C2H5OH) is a condensation reaction that forms an ether bond. The product of this reaction is the crystalized sulfanilamide.

To determine the chemical equation, you need to consider the functional groups in sulfanilamide and ethyl alcohol.

Sulfanilamide contains an amine group (NH2) and a carbonyl group (C=O). Ethyl alcohol contains a hydroxyl group (OH) and an alkyl group (C2H5).

The reaction between sulfanilamide and ethyl alcohol involves the condensation of the carbonyl group in sulfanilamide with the hydroxyl group in ethyl alcohol, forming an ether linkage.

So, the chemical equation for the reaction between sulfanilamide and ethyl alcohol can be written as:

C6H7N3O2S + C2H5OH → C6H8N2O2S + H2O

In this equation, the product formed is sulfanilamide (C6H8N2O2S) and water (H2O) is released as a byproduct.

Now that you have the balanced chemical equation, you can use it to calculate the mole ratio between sulfanilamide and ethyl alcohol, which will help you determine the theoretical yield of sulfanilamide after crystallization.

Hope this helps! Let me know if you have any further questions.