posted by Nick on .
The reaction of 9.3 grams of ﬂuorine with
excess chlorine produced 4.1 grams of ClF3.
What percent yield of ClF3 was obtained?
1. Write and balance the equation.
2. Convert 9.3 g F2 to mols. mols = grams/molar mass.
3. Using the coefficients in the balanced equation, convert mols F2 to mols of the product.l
4. Now convert mols or the product to grams. g = mols x molar mass. This is the theoretical yield(TE). Actual yield is 4.1g.
5. %yield = (actual yield/TE)*100 = ?