posted by Kieran .
if the velocity can be expressed as
v(t)=1-∛t what is the acceleration function.
so i started by bringing in acceleration formula a=v1-vo/t1-to
took my velocity function and found the derivative. v=-1/3t^2/3 have i started it correct so far and where do i go from here besides just plugging it into the acceleration form
a = dv/dt
if v = 1 - ∛t, then
a = -1/3 t^-2/3 = -1/(3∛t2)
that is the acceleration function