Posted by **Anonymous** on Monday, August 6, 2012 at 9:31pm.

Prove that sin^2(Omega) - Cos^2(Omega) / tan(Omega) sin(Omega) + cos(Omega) tan(Omega) = cos(Omega) - cot (Omega) cos (omega)

- Trigonometry -
**Reiny**, Monday, August 6, 2012 at 10:12pm
I substituted any angle in the equation the way you typed it, and the equation was false.

I then tried it as

(sin^2 Ø - cos^2 Ø)/(tanØsinØ + cosØtanØ)

using Ø instead of omega for easier typing.

and got

LS = (sinØ+cosØ)(sinØ-cosØ)/(tanØ(sinØ+cosØ)

= (sinØ - cosØ)/(sinØ/cosØ)

= cosØ(sinØ - cosØ)/sinØ

= cosØsinØ/sinØ - cos^2 Ø/sinØ

= cosØ - (cosØ/sinØ)cos‚

= cosØ - cotØcosØ

= RS

- Trigonometry -
**Anonymous**, Tuesday, August 7, 2012 at 4:43pm
What does LS and RS stand for?

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