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August 30, 2014

August 30, 2014

Posted by **Jay** on Friday, July 20, 2012 at 1:36am.

- Probability/Combinatorics -
**MathMate**, Friday, July 20, 2012 at 7:44amFirst card: any card (52/52)

Second card: one of 12 remaining cards of the same suit (12/51)

third card: one of 11 remaining cards of the same suit (11/50)

fourth card: one of 39 cards of any other suit (39/49)

Since all these are required events, use the multiplication rule to get the combined probability of all four events happening.

Odds are P(E)/(1-P(E)) where P(E) is the probability of an event taking place.

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