Post a New Question

physics

posted by .

A charge of 4.00 mC is placed at each corner of a square 1.05 m on a side. Determine the magnitude and direction of the force on each charge.

  • physics -

    q1, q2, q3,q4 –from the lower left corner – counterclockwise.
    Origin of the coordinate system is at the corner where q1 is located.

    F12=k•q1•q2/a² =
    =9•10^9•4•10^-3•4•10^-3/1.05²=
    = 130612 N
    F12x=0, F12y= - 130612 N.

    F13=k•q1•q3/ (a√2)² =
    =9•10^9•4•10^-3•4•10^-3/1.05²•1.41=
    = 92633N
    F13x=F13y= - 92633 •cos45= - 65491 N.

    F14=k•q1•q4/a² =
    =9•10^9•4•10^-3•4•10^-3/1.05²=
    = 130612 N
    F14x= - 130612 N, F14y =0 N.


    F1x= F12x+ F13x +F14x =0 - 65491- 130612 = - 196103 N,
    F1y= F12y+ F13y +F14y = - 130612 – 65491 -0= - 196103 N.
    F1=sqrt(F1x² + F1y²) =sqrt(196103² + 196103 ²) =277331 N.
    tanα = F1y/ F1x= 1
    => along the diagonal of the square, away from each charge.
    The same force acts on each charge

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question