Posted by Jennifer on .
If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time, give by g(t)= 16^2 + 64t. What is the maximum heigh reached by the ball?

Math 
bobpursley,
max height is when g is max
I think you meant
g(t)=16t^2+64t
g(t)=16t(4t) or g=0 at t=0 and t=4
so max height is at t=2, the mid point
maxheight= 16*4+64*2=64meters