Posted by **Bryce** on Thursday, June 14, 2012 at 9:11am.

If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time given y s(t) = -16t^2 + 64t. Graph this function for 0 < t<4, what is the maximum height?

- Math -
**Henry**, Friday, June 15, 2012 at 9:40pm
Tv = -B/2A = -64 / -32 = 2 s.

Y = -16*2^2 + 64*2 = 64 Ft, = Max. ht.

V(T,Y) = (2,64).

Complete the chart below for graphing.

(T,Y).

(0.5,28)

(1.0,48).

(1.5,

V(2.0,64).

(2.5,

(3.0,

(3.5,

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