Posted by Bryce on .
If a baseball is projected upward from ground level with an initial velocity of 64 feet per second, then its height is a function of time given y s(t) = 16t^2 + 64t. Graph this function for 0 < t<4, what is the maximum height?

Math 
Henry,
Tv = B/2A = 64 / 32 = 2 s.
Y = 16*2^2 + 64*2 = 64 Ft, = Max. ht.
V(T,Y) = (2,64).
Complete the chart below for graphing.
(T,Y).
(0.5,28)
(1.0,48).
(1.5,
V(2.0,64).
(2.5,
(3.0,
(3.5,