Posted by Rina on .
How would I go about solving for x in the equation:
ln(4x2)ln(4)=ln(x2)
Thanks in advance

College Algebra 
drwls,
ln[(4x2)/4] = ln[1/(x2)]
(4x 2)/4 = 1/(x2)
x  1/2 = 1/(x2)
x^2 x/2 2x +1 = 1
x^2 (5/2)x = 0
x = 0 or 5/2
0 is not allowed since ln of a negative number is undefined
x = 5/2