Brandy is made by distilling ethyl alcohol,

which is done by boiling the alcohol until it
turns into a gas. How much heat is required
to completely distil 0.750 kg of ethyl alcohol?

To determine the amount of heat required to completely distill 0.750 kg of ethyl alcohol, we need to know the heat of vaporization of ethyl alcohol. This value represents the amount of heat needed to convert one unit of substance from a liquid to a gas at a specific temperature and pressure.

The heat of vaporization for ethyl alcohol, also known as its enthalpy of vaporization, is approximately 855 kJ/mol. To use this value, we need to convert the mass of ethyl alcohol provided into moles.

The molar mass of ethyl alcohol (C2H5OH) is approximately 46.07 g/mol. By dividing the given mass of 0.750 kg (750 g) by the molar mass, we can find the number of moles:

Number of moles = Mass / Molar mass
Number of moles = 750 g / 46.07 g/mol ≈ 16.29 mol

Now that we have the number of moles, we can calculate the heat required for vaporization using the following equation:

Heat = Number of moles × Heat of vaporization

Heat = 16.29 mol × 855 kJ/mol ≈ 13,940 kJ

Therefore, approximately 13,940 kJ of heat is required to completely distill 0.750 kg of ethyl alcohol.