Tuesday

March 31, 2015

March 31, 2015

Posted by **logan** on Tuesday, May 29, 2012 at 7:32am.

- math/algebra -
**bobpursley**, Tuesday, May 29, 2012 at 8:06am(55/60)/(11/3)= 55*3/(60*11)=165/660

and you can reduce that

33/220

- math/algebra -
**me**, Tuesday, May 29, 2012 at 1:01pmI don't know where 'bobpursley' learned his math, or why he keeps answering math questions on this site incorrectly, but here's how it's actually done.

There are 60 minutes in an hour, so 55 minutes can be expressed, very simply, as 55 / 60

To reduce this fraction, look for a common factor in 55 and 60; in this case 5. So dividing by 5, both top & bottom, 55 / 60 = 11 / 12

Now to express 11 / 12 (55 minutes) as a fraction of 11 / 3 hours, simply divide them:

(11 / 12) / (11 / 3)

But remember, whenever you divide by a fraction, you can simply multiply by its reciprocal, so it becomes:

(11 / 12) * (3 / 11)

You see that the 11's cancel out, so multiplying across you get:

3 / 12

which simplifies down to

1 / 4

----- OR -----

Alternatively, you can multiply (11 / 3) by 60, to find out how many minutes is in (11 / 3) hours. So, (11 / 3) * 60 = 220 minutes

Now divide 55 by 220 and reduce:

(55 / 220)

= 1 / 4

**Answer this Question**

**Related Questions**

algebra - Express 55 minutes as a fraction of 11/3 hours. please this is doen.

math - 6. If each of eight biology classrooms is in use for 5 hours and 15 ...

math - use : .# x 6 = minutes I did try to do it but came up with numbers like 5...

math - Vanessa typically works 8 hours per day in a normal 5 day work week. Last...

math - express 55 minutes as a fraction of 1 1/3 hours

math - Andrew worked from 9:45 am to 3:40 pm on Saturday.how long did he work on...

math - Shelby can paint a room in 4 hours. Zoe can paint the same room in 7 ...

third grade math - reed's bookstore is open 9 hours each day. it opens at 9:30a....

Math - Q. Sidney flew in an airplane five times during her vacation. The flights...

Math - 1. Mackenzie spent a lot of time on her project for Columbus Day. On ...