Posted by **Cj** on Wednesday, May 9, 2012 at 11:31am.

Jeff wants to start a lawn maintenance service to earn money for college. He wants to charge $25 for a small lawn and $35 for a large one. It takes him an average of 2 hours to mow and trim a small lawn and 3 hours to do a large one. He wants to make at least $250 a week but can work no more than 20 hours every week.

If x is the number of small lawns and y is the number of large lawns, which ordered pair is a solution to the system of inequalities which describes Jeff's situation?

- math -
**Steve**, Wednesday, May 9, 2012 at 1:10pm
Don't see any choices, but we do know

2x + 3y <= 20

25x + 35y >= 250

If he does 10 small lawns, that's 20 hrs and $250

He can't do any large lawns, since he can do at most 8 small lawns for $200, and can't make up the difference and stay under 20 hours:

S L Hrs $$$

10 0 20 250

9 0 18 225

8 1 19 235

7 2 20 245

6 2 18 220

. . .

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