A 10.67 kg bowling ball has speed 4.35 m/s before hitting the floor. A(n) 66.5 g golf ball flies at much higher speed, so the two balls have exactly same kinetic energy. What is the speed of the golf ball?

Note: neglect rotation of either ball. Answer in units of m/s.

0.5m1*V1^2 = 0.5m2*V2^2.

5.335*(4.35)^2 = 0.03325*V2^2
0.03325V2^2 = 100.95
V2^2 = 100.95 / 0.03325 = 3036
V2 = 55.1 m/s.

To find the speed of the golf ball, we need to use the concept of kinetic energy.

The formula for kinetic energy is given by:

KE = (1/2) * mass * velocity^2

We are told that the kinetic energy of the bowling ball is the same as the kinetic energy of the golf ball. Let's denote the mass of the golf ball as m and its velocity as v.

For the bowling ball:
KE_bowling = (1/2) * 10.67 kg * (4.35 m/s)^2

For the golf ball:
KE_golf = (1/2) * 0.0665 kg * v^2

Since the kinetic energy is the same for both balls, we can set up the equation:

(1/2) * 10.67 kg * (4.35 m/s)^2 = (1/2) * 0.0665 kg * v^2

Now we can solve for v:

(10.67 kg * (4.35 m/s)^2) / (0.0665 kg) = v^2

Rearranging the equation:

v^2 = (10.67 kg * (4.35 m/s)^2) / (0.0665 kg)

Simplifying:

v^2 = 3076.11 m^2/s^2

Taking the square root of both sides to find the speed:

v = √(3076.11 m^2/s^2)

Calculating the value:

v ≈ 55.53 m/s

Therefore, the speed of the golf ball is approximately 55.53 m/s.