Posted by **Yadira** on Monday, April 30, 2012 at 12:23am.

Prove the identit: cosxcotx+sinx=cscx

- Pre-Calc/Math -
**visoth**, Monday, April 30, 2012 at 1:00am
1) rewrite cosx (cosx/sinx) + sinx = csc x

2) cosx^2/sinx + sinx = csc x

3) multiply sinx by (sinx/sinx) to get same denominator

this gives you cosx^2/sinx + sinx^2/sinx = cscx

4) combine your fractions

(cosx^2 + sinx^2)/sinx = cscx

5) rewrite numerator

1/sinx= csc x

and there you go it is proven (you have to know your trig identity to do this so look them up if you don't know them)

- Pre-Calc/Math -
**Yadira**, Monday, April 30, 2012 at 1:05am
Thank You! :D

- Pre-Calc/Math -
**visoth**, Monday, April 30, 2012 at 1:11am
no problem lol this one almost had me stump for alittle

- Pre-Calc/Math -
**Yadira**, Monday, April 30, 2012 at 1:11am
Ohh it was hard me :/ .Do you think you can answer my other questions?

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