Posted by Mima on Saturday, April 7, 2012 at 6:15pm.
CO2 + H2O ==> H2CO3
dGrxn = (dG products) - (dG reactants)
Then dG = -RTlnK
Solve for K.
Then H2CO3 ==> H^+ + HCO3^-
k1 = 4.5E-7
For the two reactions together you have
CO2 + H2O ==>H^+ + HCO3^- and Keq = k1K.
Finally, convert pH 4.78 to H^+, substitute into the equation (HCO3^- = H^+ too) and solve for partial pressure of CO2.
Thank you so much for replying, but I can't understand how to solve for partial pressure of CO2, when I get the [H^+] from PH then how to solve for partial pressure of CO2?
Thanks a lot, I got it.
I kept record of all IP addresses and they will be reported to UCI undergrad offices.
@Amanda lolololol
@Amanda, k
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