Posted by Chantel on .
Given PV=nRT and the following equation:
Calculate the maximum number of ML of CO2 at 750 torr and 295.15 degrees K that can be formed from above conbution of methane ( CH4 ) if 450 mL of methane at 705 torr and 283.15 degrees K are mixed with 725 mL of O2 at 680 torr at 353.15 degrees K
Use PV = nRT and convert CH4 to moles.
Do the same for O2.
This is a limiting reagent problem; determine the limiting reagent.
Use the limiting reagent as a single stoichiometry problem to calculate the number of mols CO2 produced, then use PV = nRT to convert to L. Multiply by 1000 to convert to mL.