Posted by Mary on Saturday, March 10, 2012 at 8:35pm.
Divide total energy gain by 120 seconds for the energy of power delivered by the engine.
P.E. gain = M g H = 1.746*10^6 J
K.E. loss = (M/2)(V1^2 - V2^2)
V1 = 40.28 m/s
V2 = 25.00 m/s
K.E. loss = 2.992*10^5 J
Net energy gain = 1.465*10^6 J
Power during interval = 1.465*10^6/120 = 12210 W = 164 horsepower
This is an underestimate because there is also air friction drag that the engine must overcome, and because the propellers are not 100% efficient
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