Wednesday

October 1, 2014

October 1, 2014

Posted by **Mary** on Saturday, March 10, 2012 at 8:35pm.

- physics -
**drwls**, Sunday, March 11, 2012 at 7:38amDivide total energy gain by 120 seconds for the energy of power delivered by the engine.

P.E. gain = M g H = 1.746*10^6 J

K.E. loss = (M/2)(V1^2 - V2^2)

V1 = 40.28 m/s

V2 = 25.00 m/s

K.E. loss = 2.992*10^5 J

Net energy gain = 1.465*10^6 J

Power during interval = 1.465*10^6/120 = 12210 W = 164 horsepower

This is an underestimate because there is also air friction drag that the engine must overcome, and because the propellers are not 100% efficient

**Answer this Question**

**Related Questions**

physics - An airplane needs at least 145 meters of runway to take off. If the ...

Math - You observe a plane approaching overhead at a speed of 600 mph. The angle...

physics - A Boeing 787 is initially moving down the runway at 3.0 m/s preparing ...

ALGEBRA 2 - A plane takes off from an aiport and flies east at a speed of 350 mi...

Physics - A jet plane lands with a speed of 110 m/s and can accelerate with a ...

Velocity and Displacement - A plane is sitting on a runway, awaiting takeoff. On...

Physics - A jet plane has a takeoff speed of Vto=125km/h (34.72 m/s) and it's ...

math - At an airport, a flight controller was in a tower 40m above the ground. ...

physics - a plane on a runway accelerates from rest for 6.8 seconds. If the ...

physics - A small plane starts down the runway with acceleration 7.4 .if the ...