Posted by Veronica on Wednesday, February 29, 2012 at 9:55pm.
solve using the gaussjordan method.
x2y+4z=7
x+3yz=1
2x+y=2
*I get through the first two columbs, but can't get the third one to the one and zero.

mathmatrix  Damon, Wednesday, February 29, 2012 at 10:09pm
http://www.irs.gov/pub/irspdf/i1040tt.pdf
Step 2: Enter the values for your matrix, and press the "Solve" button.
three rows, four columns
Input
+1 2 +4 +7
1 +3 1 1
+2 +1 +0 2
Add (1 * row1) to row2
1 2 4 7
0 1 3 6
2 1 0 2
Add (2 * row1) to row3
1 2 4 7
0 1 3 6
0 5 8 16
Add (5 * row2) to row3
1 2 4 7
0 1 3 6
0 0 23 46
Divide row3 by 23
1 2 4 7
0 1 3 6
0 0 1 2
Add (3 * row3) to row2
1 2 4 7
0 1 0 0
0 0 1 2
Add (4 * row3) to row1
1 2 0 1
0 1 0 0
0 0 1 2
Add (2 * row2) to row1
1 0 0 1
0 1 0 0
0 0 1 2

link correction  Damon, Wednesday, February 29, 2012 at 10:11pm
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx

mathmatrix  Veronica, Wednesday, February 29, 2012 at 10:18pm
thanks, wasn't too sure whether I could divide by 23 or not. Found the website, was really helpfull =)
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